Answer
$$(x+y+z)^2=x^2+2xy+2xz+y^2+2yz+z^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+y+z)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2+2xy+2xz+y^2+2yz+z^2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+y+z}\right) $ by each term in $ \left( x+y+z\right) $. $$ \left( \color{blue}{x+y+z}\right) \cdot \left( x+y+z\right) = x^2+xy+xz+xy+y^2+yz+xz+yz+z^2 $$ |
| ② | Combine like terms: $$ x^2+ \color{blue}{xy} + \color{red}{xz} + \color{blue}{xy} +y^2+ \color{green}{yz} + \color{red}{xz} + \color{green}{yz} +z^2 = \\ = x^2+ \color{blue}{2xy} + \color{red}{2xz} +y^2+ \color{green}{2yz} +z^2 $$ |
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