Find roots of polynomial $$ p(x) = z^2+6z+10 $$
Answer
The roots of polynomial $ p(z) $ are:
$$ \begin{aligned}z_1 &= -3+i\\[1 em]z_2 &= -3-i \end{aligned} $$Explanation
The solutions of $ z^2+6z+10 = 0 $ are: $ z = -3+i ~ \text{and} ~ z = -3-i$.
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