Find roots of polynomial $$ p(x) = y^4-2 $$
Answer
The roots of polynomial $ p(y) $ are:
$$ \begin{aligned}y_1 &= 1.1892\\[1 em]y_2 &= -1.1892\\[1 em]y_3 &= 1.1892i\\[1 em]y_4 &= -1.1892i \end{aligned} $$Explanation
Polynomial $ y^4-2 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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