Find roots of polynomial $$ p(x) = y^2-22y+112 $$
Answer
The roots of polynomial $ p(y) $ are:
$$ \begin{aligned}y_1 &= 14\\[1 em]y_2 &= 8 \end{aligned} $$Explanation
The solutions of $ y^2-22y+112 = 0 $ are: $ y = 8 ~ \text{and} ~ y = 14$.
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