Find roots of polynomial $$ p(x) = x^6+2x^5+x^4+7x^3+20x^2-x+4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.0561+0.4376i\\[1 em]x_2 &= 0.0561-0.4376i\\[1 em]x_3 &= -2.0438+0.9293i\\[1 em]x_4 &= -2.0438-0.9293i\\[1 em]x_5 &= 0.9877+1.761i\\[1 em]x_6 &= 0.9877-1.761i \end{aligned} $$Explanation
Polynomial $ x^6+2x^5+x^4+7x^3+20x^2-x+4 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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