Find roots of polynomial $$ p(x) = x^6-x^5-x^4-x^3-3x^2-3x-1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.6823\\[1 em]x_2 &= 2.1479\\[1 em]x_3 &= -0.574+0.369i\\[1 em]x_4 &= -0.574-0.369i\\[1 em]x_5 &= 0.3412+1.1615i\\[1 em]x_6 &= 0.3412-1.1615i \end{aligned} $$Explanation
Polynomial $ x^6-x^5-x^4-x^3-3x^2-3x-1 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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