Find roots of polynomial $$ p(x) = x^6-x^4+125x^3-x^2+1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.1973\\[1 em]x_2 &= -5.0692\\[1 em]x_3 &= 0.1026+0.1733i\\[1 em]x_4 &= 0.1026-0.1733i\\[1 em]x_5 &= 2.5306+4.2722i\\[1 em]x_6 &= 2.5306-4.2722i \end{aligned} $$Explanation
Polynomial $ x^6-x^4+125x^3-x^2+1 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
This page was created using
Polynomial Roots Calculator