Find roots of polynomial $$ p(x) = x^6-3x^4-18x^2+40 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.4142\\[1 em]x_2 &= -1.4142\\[1 em]x_3 &= 2.2361\\[1 em]x_4 &= -2.2361\\[1 em]x_5 &= 2i\\[1 em]x_6 &= -2i \end{aligned} $$Explanation
Polynomial $ x^6-3x^4-18x^2+40 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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