Find roots of polynomial $$ p(x) = x^5-4x^4-7x^3+x^2-3x+4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.6466\\[1 em]x_2 &= -1.6761\\[1 em]x_3 &= 5.3002\\[1 em]x_4 &= -0.1353+0.8234i\\[1 em]x_5 &= -0.1353-0.8234i \end{aligned} $$Explanation
Polynomial $ x^5-4x^4-7x^3+x^2-3x+4 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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