Find roots of polynomial $$ p(x) = x^5-3x^3+x^2-9 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.9316\\[1 em]x_2 &= 0.5898+1.1934i\\[1 em]x_3 &= 0.5898-1.1934i\\[1 em]x_4 &= -1.5556+0.4574i\\[1 em]x_5 &= -1.5556-0.4574i \end{aligned} $$Explanation
Polynomial $ x^5-3x^3+x^2-9 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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