Find roots of polynomial $$ p(x) = x^5-3x^2+100 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -2.4169\\[1 em]x_2 &= 2.0615+1.3859i\\[1 em]x_3 &= 2.0615-1.3859i\\[1 em]x_4 &= -0.853+2.4449i\\[1 em]x_5 &= -0.853-2.4449i \end{aligned} $$Explanation
Polynomial $ x^5-3x^2+100 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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