Find roots of polynomial $$ p(x) = x^5-2x^2-14 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.8336\\[1 em]x_2 &= 0.412+1.5298i\\[1 em]x_3 &= 0.412-1.5298i\\[1 em]x_4 &= -1.3288+1.1297i\\[1 em]x_5 &= -1.3288-1.1297i \end{aligned} $$Explanation
Polynomial $ x^5-2x^2-14 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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