Find roots of polynomial $$ p(x) = x^4+3x^2-x+3 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.41+1.0288i\\[1 em]x_2 &= 0.41-1.0288i\\[1 em]x_3 &= -0.41+1.5093i\\[1 em]x_4 &= -0.41-1.5093i \end{aligned} $$Explanation
Polynomial $ x^4+3x^2-x+3 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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