Find roots of polynomial $p (x) = x^{4} + 2 x^{2} + 1$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} x_{3} x_{4} = i = - i = i = - i$

Explanation

Polynomial $x^{4} + 2 x^{2} + 1$ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.

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Find roots of polynomial p(x)=x4+2x2+1

The roots of polynomial p(x) are: x1​x2​x3​x4​​=i=−i=i=−i​

Find roots of polynomial $p (x) = x^{4} + 2 x^{2} + 1$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} x_{3} x_{4} = i = - i = i = - i$