Find roots of polynomial $$ p(x) = x^4-8x^2+x+12 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.5616\\[1 em]x_2 &= -1.3028\\[1 em]x_3 &= 2.3028\\[1 em]x_4 &= -2.5616 \end{aligned} $$Explanation
Polynomial $ x^4-8x^2+x+12 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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