Find roots of polynomial $$ p(x) = x^4-7x^3-6x^2+12x+8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.6267\\[1 em]x_2 &= -1.2685\\[1 em]x_3 &= 1.3302\\[1 em]x_4 &= 7.565 \end{aligned} $$Explanation
Polynomial $ x^4-7x^3-6x^2+12x+8 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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