The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.1914+1.0651i\\[1 em]x_2 &= -0.1914-1.0651i\\[1 em]x_3 &= 1.6914+1.5043i\\[1 em]x_4 &= 1.6914-1.5043i \end{aligned} $$Polynomial $ x^4-3x^3+5x^2-2x+6 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.