Find roots of polynomial $$ p(x) = x^4-3x^3+2x^2+12 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.6953+1.2108i\\[1 em]x_2 &= -0.6953-1.2108i\\[1 em]x_3 &= 2.1953+1.156i\\[1 em]x_4 &= 2.1953-1.156i \end{aligned} $$Explanation
Polynomial $ x^4-3x^3+2x^2+12 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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