Find roots of polynomial $$ p(x) = x^4-14x^2-32x $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= 4.581\\[1 em]x_3 &= -2.2905+1.3187i\\[1 em]x_4 &= -2.2905-1.3187i \end{aligned} $$Explanation
Step 1:
Factor out $ \color{blue}{ x }$ from $ x^4-14x^2-32x $ and solve two separate equations:
$$ \begin{aligned} x^4-14x^2-32x & = 0\\[1 em] \color{blue}{ x }\cdot ( x^3-14x-32 ) & = 0 \\[1 em] \color{blue}{ x = 0} ~~ \text{or} ~~ x^3-14x-32 & = 0 \end{aligned} $$One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.
Step 2:
Polynomial $ x^3-14x-32 $ has no rational roots that can be found using Rational Root Test, so the roots were found using qubic formulas.
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