Find roots of polynomial $$ p(x) = x^4-10x^3+20x^2-2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.3465\\[1 em]x_2 &= -0.2947\\[1 em]x_3 &= 2.7036\\[1 em]x_4 &= 7.2446 \end{aligned} $$Explanation
Polynomial $ x^4-10x^3+20x^2-2 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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