Find roots of polynomial $p (x) = x^{3} + x + 1$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} x_{3} = - 0.6823 = 0.3412 + 1.1615 i = 0.3412 - 1.1615 i$

Explanation

Polynomial $x^{3} + x + 1$ has no rational roots that can be found using Rational Root Test, so the roots were found using qubic formulas.

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Find roots of polynomial p(x)=x3+x+1

The roots of polynomial p(x) are: x1​x2​x3​​=−0.6823=0.3412+1.1615i=0.3412−1.1615i​

Find roots of polynomial $p (x) = x^{3} + x + 1$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} x_{3} = - 0.6823 = 0.3412 + 1.1615 i = 0.3412 - 1.1615 i$