The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= 4 \end{aligned} $$Step 1:
Factor out $ \color{blue}{ x }$ from $ x^3-8x^2+16x $ and solve two separate equations:
$$ \begin{aligned} x^3-8x^2+16x & = 0\\[1 em] \color{blue}{ x }\cdot ( x^2-8x+16 ) & = 0 \\[1 em] \color{blue}{ x = 0} ~~ \text{or} ~~ x^2-8x+16 & = 0 \end{aligned} $$One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.
Step 2:
The solution of $ ~ x^2-8x+16 = 0 ~$ is $~ x = 4 ~$.
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