Find roots of polynomial $$ p(x) = x^3-7x^2+16x+12 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.5868\\[1 em]x_2 &= 3.7934+2.4621i\\[1 em]x_3 &= 3.7934-2.4621i \end{aligned} $$Explanation
Polynomial $ x^3-7x^2+16x+12 $ has no rational roots that can be found using Rational Root Test, so the roots were found using qubic formulas.
This page was created using
Polynomial Roots Calculator