Find roots of polynomial $$ p(x) = x^3 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= 0 \end{aligned} $$Explanation
$$ \begin{aligned} x^3 & = 0 \\[1 em] x & = 0 \end{aligned} $$
Multiplicity of this zero is equal to 3.
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