Find roots of polynomial $p (x) = x^{2} + x + 1$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = - \frac{1}{2} + \frac{3}{2} i = - \frac{1}{2} - \frac{3}{2} i$

Explanation

The solutions of $x^{2} + x + 1 = 0$ are: $x = - \frac{1}{2} + \frac{3}{2} i and x = - \frac{1}{2} - \frac{3}{2} i$ .

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.

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Find roots of polynomial $p (x) = x^{2} + x + 1$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = - \frac{1}{2} + \frac{3}{2} i = - \frac{1}{2} - \frac{3}{2} i$