Find roots of polynomial $$ p(x) = x^2+6+8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \sqrt{ 14 }i\\[1 em]x_2 &= -\sqrt{ 14 }i \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ x^2+ \color{blue}{6} + \color{blue}{8} = x^2+ \color{blue}{14} $$Step 2:
The solutions of $ x^2+14 = 0 $ are: $ x = \sqrt{ 14 } i ~ \text{and} ~ x = -\sqrt{ 14 } i $.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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