Find roots of polynomial $$ p(x) = x^2+60x+100 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1.7157\\[1 em]x_2 &= -58.2843 \end{aligned} $$Explanation
The solutions of $ x^2+60x+100 = 0 $ are: $ x = -30-20 \sqrt{ 2 } ~ \text{and} ~ x = -30+20 \sqrt{ 2 }$.
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