Find roots of polynomial $$ p(x) = x^2+\frac{5}{6}x-\frac{1}{6} $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 1 }{ 6 }\\[1 em]x_2 &= -1 \end{aligned} $$Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 6 } $.
$$ \begin{aligned} x^2+\frac{5}{6}x-\frac{1}{6} & = 0 ~~~ / \cdot \color{blue}{ 6 } \\[1 em] 6x^2+5x-1 & = 0 \end{aligned} $$Step 2:
The solutions of $ 6x^2+5x-1 = 0 $ are: $ x = -1 ~ \text{and} ~ x = \dfrac{ 1 }{ 6 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator