Find roots of polynomial $$ p(x) = x^2+420x-1900 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.4761\\[1 em]x_2 &= -424.4761 \end{aligned} $$Explanation
The solutions of $ x^2+420x-1900 = 0 $ are: $ x = -210-20 \sqrt{ 115 } ~ \text{and} ~ x = -210+20 \sqrt{ 115 }$.
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