Find roots of polynomial $$ p(x) = x^2+310x+7400 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -26.062\\[1 em]x_2 &= -283.938 \end{aligned} $$Explanation
The solutions of $ x^2+310x+7400 = 0 $ are: $ x = -155-5 \sqrt{ 665 } ~ \text{and} ~ x = -155+5 \sqrt{ 665 }$.
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