Find roots of polynomial $$ p(x) = x^2+24x-288 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 8.7846\\[1 em]x_2 &= -32.7846 \end{aligned} $$Explanation
The solutions of $ x^2+24x-288 = 0 $ are: $ x = -12-12 \sqrt{ 3 } ~ \text{and} ~ x = -12+12 \sqrt{ 3 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator