The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 7.3205\\[1 em]x_2 &= -27.3205 \end{aligned} $$The solutions of $ x^2+20x-200 = 0 $ are: $ x = -10-10 \sqrt{ 3 } ~ \text{and} ~ x = -10+10 \sqrt{ 3 }$.
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