Find roots of polynomial $$ p(x) = x^2+18x+30 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1.8586\\[1 em]x_2 &= -16.1414 \end{aligned} $$Explanation
The solutions of $ x^2+18x+30 = 0 $ are: $ x = -9-\sqrt{ 51 } ~ \text{and} ~ x = -9+\sqrt{ 51 }$.
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