Find roots of polynomial $$ p(x) = x^2+170-8400 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \sqrt{ 8230 }\\[1 em]x_2 &= -\sqrt{ 8230 } \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ x^2+ \color{blue}{170} \color{blue}{-8400} = x^2 \color{blue}{-8230} $$Step 2:
The solutions of $ x^2-8230 = 0 $ are: $ x = -\sqrt{ 8230 } ~ \text{and} ~ x = \sqrt{ 8230 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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