Find roots of polynomial $$ p(x) = x^2+14x+47 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -5.5858\\[1 em]x_2 &= -8.4142 \end{aligned} $$Explanation
The solutions of $ x^2+14x+47 = 0 $ are: $ x = -7-\sqrt{ 2 } ~ \text{and} ~ x = -7+\sqrt{ 2 }$.
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