Find roots of polynomial $$ p(x) = x^2+10x-93 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 5.8628\\[1 em]x_2 &= -15.8628 \end{aligned} $$Explanation
The solutions of $ x^2+10x-93 = 0 $ are: $ x = -5-\sqrt{ 118 } ~ \text{and} ~ x = -5+\sqrt{ 118 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator