Find roots of polynomial $$ p(x) = x^2-x-2+1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.618\\[1 em]x_2 &= -0.618 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ x^2-x \color{blue}{-2} + \color{blue}{1} = x^2-x \color{blue}{-1} $$Step 2:
The solutions of $ x^2-x-1 = 0 $ are: $ x = \dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 5 }}{ 2 } ~ \text{and} ~ x = \dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 5 }}{ 2 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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