Find roots of polynomial $$ p(x) = x^2-8x+17 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4+i\\[1 em]x_2 &= 4-i \end{aligned} $$Explanation
The solutions of $ x^2-8x+17 = 0 $ are: $ x = 4+i ~ \text{and} ~ x = 4-i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator