Find roots of polynomial $$ p(x) = x^2-6x+7 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.4142\\[1 em]x_2 &= 1.5858 \end{aligned} $$Explanation
The solutions of $ x^2-6x+7 = 0 $ are: $ x = 3-\sqrt{ 2 } ~ \text{and} ~ x = 3+\sqrt{ 2 }$.
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