Find roots of polynomial $$ p(x) = x^2-6x-27+x-9 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 9\\[1 em]x_2 &= -4 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ x^2 \color{blue}{-6x} \color{red}{-27} + \color{blue}{x} \color{red}{-9} = x^2 \color{blue}{-5x} \color{red}{-36} $$Step 2:
The solutions of $ x^2-5x-36 = 0 $ are: $ x = -4 ~ \text{and} ~ x = 9$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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