Find roots of polynomial $$ p(x) = x^2-60x+747 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 42.3693\\[1 em]x_2 &= 17.6307 \end{aligned} $$Explanation
The solutions of $ x^2-60x+747 = 0 $ are: $ x = 30-3 \sqrt{ 17 } ~ \text{and} ~ x = 30+3 \sqrt{ 17 }$.
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