Find roots of polynomial $$ p(x) = x^2-50x-400 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 57.0156\\[1 em]x_2 &= -7.0156 \end{aligned} $$Explanation
The solutions of $ x^2-50x-400 = 0 $ are: $ x = 25-5 \sqrt{ 41 } ~ \text{and} ~ x = 25+5 \sqrt{ 41 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator