Find roots of polynomial $$ p(x) = x^2-4x+13 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2+3i\\[1 em]x_2 &= 2-3i \end{aligned} $$Explanation
The solutions of $ x^2-4x+13 = 0 $ are: $ x = 2+3i ~ \text{and} ~ x = 2-3i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator