Find roots of polynomial $$ p(x) = x^2-45x+300 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 36.8614\\[1 em]x_2 &= 8.1386 \end{aligned} $$Explanation
The solutions of $ x^2-45x+300 = 0 $ are: $ x = \dfrac{ 45 }{ 2 }-\dfrac{ 5 \sqrt{ 33}}{ 2 } ~ \text{and} ~ x = \dfrac{ 45 }{ 2 }+\dfrac{ 5 \sqrt{ 33}}{ 2 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator