Find roots of polynomial $$ p(x) = x^2-3x-9 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.8541\\[1 em]x_2 &= -1.8541 \end{aligned} $$Explanation
The solutions of $ x^2-3x-9 = 0 $ are: $ x = \dfrac{ 3 }{ 2 }-\dfrac{ 3 \sqrt{ 5}}{ 2 } ~ \text{and} ~ x = \dfrac{ 3 }{ 2 }+\dfrac{ 3 \sqrt{ 5}}{ 2 }$.
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