Find roots of polynomial $$ p(x) = x^2-3x^2-6x+8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1\\[1 em]x_2 &= -4 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ \color{blue}{x^2} \color{blue}{-3x^2} -6x+8 = \color{blue}{-2x^2} -6x+8 $$Step 2:
The solutions of $ -2x^2-6x+8 = 0 $ are: $ x = -4 ~ \text{and} ~ x = 1$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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