Find roots of polynomial $$ p(x) = x^2-3034x+\frac{7009280}{24} $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2934.4751\\[1 em]x_2 &= 99.5249 \end{aligned} $$Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 24 } $.
$$ \begin{aligned} x^2-3034x+\frac{7009280}{24} & = 0 ~~~ / \cdot \color{blue}{ 24 } \\[1 em] 24x^2-72816x+7009280 & = 0 \end{aligned} $$Step 2:
The solutions of $ 24x^2-72816x+7009280 = 0 $ are: $ x = 1517-\dfrac{ 37 \sqrt{ 13209}}{ 3 } ~ \text{and} ~ x = 1517+\dfrac{ 37 \sqrt{ 13209}}{ 3 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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