Find roots of polynomial $p (x) = x^{2} - 2 x$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = 0 = 2$

Explanation

Step 1:

Factor out $x$ from $x^{2} - 2 x$ and solve two separate equations:

x^{2} - 2 x x \cdot (x - 2) x = 0 or x - 2 = 0 = 0 = 0

One solution is $x = 0$ . Use second equation to find the remaining roots.

Step 2:

To find the second zero, solve equation $x - 2 = 0$

x - 2 x = 0 = 2

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Find roots of polynomial p(x)=x2−2x

The roots of polynomial p(x) are: x1​x2​​=0=2​

Find roots of polynomial $p (x) = x^{2} - 2 x$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = 0 = 2$