Find roots of polynomial $$ p(x) = x^2-24x-20 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 24.8062\\[1 em]x_2 &= -0.8062 \end{aligned} $$Explanation
The solutions of $ x^2-24x-20 = 0 $ are: $ x = 12-2 \sqrt{ 41 } ~ \text{and} ~ x = 12+2 \sqrt{ 41 }$.
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