Find roots of polynomial $$ p(x) = x^2-2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \sqrt{ 2 }\\[1 em]x_2 &= -\sqrt{ 2 } \end{aligned} $$Explanation
The solutions of $ x^2-2 = 0 $ are: $ x = -\sqrt{ 2 } ~ \text{and} ~ x = \sqrt{ 2 }$.
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